9x^2-252=0

Solution for 9x^2-252=0 equation:

9x^2-252=0

a = 9; b = 0; c = -252;
Δ = b2-4ac
Δ = 02-4·9·(-252)
Δ = 9072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9072}=\sqrt{1296*7}=\sqrt{1296}*\sqrt{7}=36\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{7}}{2*9}=\frac{0-36\sqrt{7}}{18}
=-\frac{36\sqrt{7}}{18}
=-2\sqrt{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{7}}{2*9}=\frac{0+36\sqrt{7}}{18}
=\frac{36\sqrt{7}}{18}
=2\sqrt{7}
$